The total number of selections of the letters | vedclass

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(C) First,count the frequency of each letter in the phrase "ned needs nineteen nets":$n: 6$$e: 7$$d: 2$$s: 2$$t: 2$$i: 1$To find the total number of s

Vedclass · Accepted Answer

$3023$

Vedclass · Answer

(C) First,count the frequency of each letter in the phrase "ned needs nineteen nets":$n: 6$$e: 7$$d: 2$$s: 2$$t: 2$$i: 1$To find the total number of selections,we consider the number of ways to choose any number of each letter (including zero).For $n$ ($6$ occurrences),we can choose $0, 1, 2, 3, 4, 5,$ or $6$ letters,which gives $6 + 1 = 7$ options.For $e$ ($7$ occurrences),we have $7 + 1 = 8$ options.For $d$ ($2$ occurrences),we have $2 + 1 = 3$ options.For $s$ ($2$ occurrences),we have $2 + 1 = 3$ options.For $t$ ($2$ occurrences),we have $2 + 1 = 3$ options.For $i$ ($1$ occurrence),we have $1 + 1 = 2$ options.The total number of combinations is the product of these options: $7 	imes 8 	imes 3 	imes 3 	imes 3 	imes 2 = 3024$.Since the selection must contain at least one letter,we subtract the case where no letters are selected: $3024 - 1 = 3023$.

The total number of selections of the letters in the phrase "ned needs nineteen nets" is:

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